document.write( "Question 884159: The price of a can of beans was increased by 25%. How many cans can be purchased for the amount of money that was previously used to buy 500 cans? \n" ); document.write( "
Algebra.Com's Answer #534105 by Fombitz(32388)\"\" \"About 
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Previously it cost \"500X\" to buy 500 cans.
\n" ); document.write( "Now that the price is \"0.75X\" 500 cans only cost, \"500%280.75%29X=375X\"
\n" ); document.write( "So you have \"500X-375X=125X\" left over.
\n" ); document.write( "Then you can buy an extra Y cans.
\n" ); document.write( "\"Y=125X%2F%280.75X%29=166.7\" cans.
\n" ); document.write( "Since you can only buy an integer number of cans, you can buy an extra 166 cans which makes a total of 666 cans.
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