document.write( "Question 884233: consider the hypothesis test with\r
\n" ); document.write( "\n" ); document.write( "Null hypothesis H0: u= 500
\n" ); document.write( "alternative hypothesis H1 u not equal 500 (this is two-tailed test)\r
\n" ); document.write( "\n" ); document.write( "In a random sample of 81 subjects, the sample mean found to be x=492. Population standard deviation is 36.\r
\n" ); document.write( "\n" ); document.write( "1. Calculate test statistics and find p-value for this test
\n" ); document.write( "2. With significance level a=0.02 (two tail test) make the decision: accept or reject H0. Explain your decision.
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Algebra.Com's Answer #534100 by Theo(13342)\"\" \"About 
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test assumption is that the mean is not equal to 500.
\n" ); document.write( "sample size = 81
\n" ); document.write( "sample mean = 492
\n" ); document.write( "population standard deviation = 36.\r
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\n" ); document.write( "\n" ); document.write( "standard error = population standard deviation divided by square root of sample size = 36 / sqrt(81) = 36/9 = 4\r
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\n" ); document.write( "\n" ); document.write( "z score = (sample mean minus popjulation mean) / standard error = (492 - 500) / 4 = -8/4 = -2\r
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\n" ); document.write( "\n" ); document.write( "test alpha = .0228 from the z score table. this is the area under the distribution curve that is to the left of a z score of -2.\r
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\n" ); document.write( "\n" ); document.write( "since the critical alpha = .02 and the test alpha is greater than this, the results are not statistically significant and you do not reject the null hypothesis in favor of the alternate hypothesis.\r
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\n" ); document.write( "\n" ); document.write( "z score table used can be found at the following link:
\n" ); document.write( "http://lilt.ilstu.edu/dasacke/eco148/ztable.htm
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