document.write( "Question 74399This question is from textbook Prentice Hall Algebra 1 Practice Workbook
\n" ); document.write( ": 1. Twenty more than the square of a number is twelve times the number. find the numbers.
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\n" ); document.write( "\n" ); document.write( "2. The Product of three more than a number times two less than the number is fourteen. Find the numbers.
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\n" ); document.write( "\n" ); document.write( "3. The sum of the squares of two consecutive odd positive integers is 202. Find the numbers.
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Algebra.Com's Answer #53410 by bucky(2189)\"\" \"About 
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Problem 1: Twenty more than the square of a number is twelve times the number. find the numbers.
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\n" ); document.write( "Begin by calling the unknown number or numbers N. Squaring N gives you \"N%5E2\" and
\n" ); document.write( "20 more than that is \"N%5E2+%2B+20\". The problem then tells you that this equals 12 times
\n" ); document.write( "the number which is written as \"12N\". So the equation becomes:
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\n" ); document.write( "\"N%5E2+%2B+20+=+12N\"
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\n" ); document.write( "Get this into the standard form of a quadratic equation by subtracting 12N from both sides.
\n" ); document.write( "The result is:
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\n" ); document.write( "\"N%5E2+-+12N+%2B+20+=+0\"
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\n" ); document.write( "The left side of this equation can be factored into two terms as follows:
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\n" ); document.write( "\"%28N-10%29%2A%28N-2%29+=+0\"
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\n" ); document.write( "(You can check this by multiplying these two terms and seeing that they get you back to
\n" ); document.write( "\"N%5E2+-+12N+%2B+20\".)
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\n" ); document.write( "Notice that the factored form of the equation will be true if either \"%28N-10%29+=+0\" or if
\n" ); document.write( "\"%28N-2%29+=+0\" because if either factor equals zero, the entire left side of the equation
\n" ); document.write( "equals zero.
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\n" ); document.write( "So, one at a time set the two factors equal to zero and solve for N. From the first factor
\n" ); document.write( "you will find that \"N=10\" and from the second factor you will find that \"N=2\".
\n" ); document.write( "So your problem has two answers that work ... N = 10 and N = 2. Check these two out by
\n" ); document.write( "returning to the problem and asking yourself, \"Does 20 more than the square of 10 equal
\n" ); document.write( "12 times 10?\" This simplifies to, \"Does 20 more than 100 equal 120?\" and, of course, it
\n" ); document.write( "does. Then you can do the same with 2. \"Does 20 more than the square of 2 equal
\n" ); document.write( "12 times 2?\" This simplifies to, \"Does 20 more than 4 equal 24?\" and, of course, it does also.
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\n" ); document.write( "Problem 2: The Product of three more than a number times two less than the number is
\n" ); document.write( "fourteen. Find the numbers.
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\n" ); document.write( "Again, let N represent the unknown number or numbers. Three more than that number is
\n" ); document.write( "\"%28N%2B3%29\" and two less than that number is \"%28N-2%29\". The problem says that product of
\n" ); document.write( "these two quantities equals 14. In equation form this becomes:
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\n" ); document.write( "\"%28N%2B3%29%2A%28N-2%29+=+14\"
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\n" ); document.write( "Multiply out the left side and the equation becomes:
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\n" ); document.write( "\"N%5E2+%2B+N+-+6+=+14\"
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\n" ); document.write( "Put this into standard quadratic form by subtracting 14 from both sides to eliminate
\n" ); document.write( "the 14 on the right side of the equation. The result of this subtraction from both sides is:
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\n" ); document.write( "\"N%5E2+%2B+N+-20+=+0\"
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\n" ); document.write( "The left side of this equation factors and the factored form is:
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\n" ); document.write( "\"%28N%2B5%29%2A%28N-4%29+=+0\"
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\n" ); document.write( "Just as we did in the first problem (and for the same reason) set each of the factors equal
\n" ); document.write( "to zero and you find that \"N+=+-5\" and \"N+=+%2B4\" are the two solutions.
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\n" ); document.write( "Check by determining if (-5+3)*(-5-2) equals 14. (It does). And then determine if
\n" ); document.write( "(4+3)*(4-2) equals 14. (It does also).
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\n" ); document.write( "Problem 3: The sum of the squares of two consecutive odd positive integers is 202. Find
\n" ); document.write( "the numbers.
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\n" ); document.write( "Let N represent the odd positive integer. Then the next odd positive integer must be
\n" ); document.write( "N+2 because odd integers are always separated by an even integer in between. [Think that
\n" ); document.write( "two odd integers in a row are 3 and 5 or 7 and 9. They are always 2 apart.]
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\n" ); document.write( "The squares of these two integers are \"N%5E2\" and \"%28N%2B2%29%5E2\" which is equal to
\n" ); document.write( "\"N%5E2+%2B+4N+%2B+4\". When you add these two squares together you get:
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\n" ); document.write( "\"N%5E2+%2B+N%5E2+%2B+4N+%2B+4\" and by combining the squared terms this becomes:
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\n" ); document.write( "\"2N%5E2+%2B+4N+%2B+4\". Set this sum of the squares equal to 202 as required by the problem.
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\n" ); document.write( "\"2N%5E2+%2B+4N+%2B+4+=+202\"
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\n" ); document.write( "Then get this into standard quadratic form by subtracting 202 from both sides to eliminate the
\n" ); document.write( "202 on the right side and the equation becomes:
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\n" ); document.write( "\"2N%5E2+%2B+4N+-+198+=+0\"
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\n" ); document.write( "Simplify the problem a little by dividing both sides (all terms) by 2 to eliminate the
\n" ); document.write( "multiplier of 2 on the \"N%5E2\" term and the equation reduces to:
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\n" ); document.write( "\"N%5E2+%2B+2N+-+99+=+0\"
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\n" ); document.write( "This factors to:
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\n" ); document.write( "\"%28N+%2B+11%29%2A%28N+-+9%29+=+0\"
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\n" ); document.write( "Setting each factor equal to zero as was done in the other problems above results in
\n" ); document.write( "two answers: \"N+=+-11\" and \"N+=+9\". The problem, however, requires the answer to
\n" ); document.write( "be a positive odd number, so we ignore the negative answer for N and the answer to this
\n" ); document.write( "problem is that N = +9. The other positive odd integer is 2 plus the +9 or 11. In summary
\n" ); document.write( "the two odd positive integers you are looking for are 9 and 11.
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\n" ); document.write( "Check by finding the sum of their squares. The squares are 81 and 121 and their sum is 202
\n" ); document.write( "as is required by the problem, so the answers we got check.
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\n" ); document.write( "Hope that in these three problems you see how to work with setting up these quadratic
\n" ); document.write( "equations and you see how you can solve them by factoring, if they do factor. If they do not
\n" ); document.write( "factor you will have to use another method to solve them, and the most universal method is
\n" ); document.write( "the quadratic formula which is another lesson entirely.
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