document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=884246>Question 884246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've tried so many things to be solving equations like this. I've asked adults, friends, siblings and neighbors and no one seems to know. Please help! and the problem is :\"Please write the equations of the following lines:\"<BR>\n" );
document.write( "a) contains (6,-1) and parallel y=2/7x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #534096 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=534096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the line contains the point (6,-1) and is parallel to y = (2/7)x + 3\r<BR>\n" );
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document.write( "if the line is parallel to y = (2/7)x + 3 then it has the same slope.\r<BR>\n" );
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document.write( "the equation of the line is in the slope intercept form of y = mx + b where m is the slope and b is the y intercept.\r<BR>\n" );
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document.write( "the slope of the line is (2/7) so the slope of your new line also has to be (2/7).\r<BR>\n" );
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document.write( "start with y = (2/7)x + b\r<BR>\n" );
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document.write( "since the point (6,-1) is on the line, you can replace y with -1 and x with 6 to get:\r<BR>\n" );
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document.write( "-1 = (2/7)*6 + b\r<BR>\n" );
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document.write( "now you want to solve for b.\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "-1 = 12/7 + b\r<BR>\n" );
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document.write( "subtract 12/7 from both sides of the equation to get:\r<BR>\n" );
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document.write( "-1 - 12/7 = b\r<BR>\n" );
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document.write( "since -1 is the same as -7/7, your equation becomes:\r<BR>\n" );
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document.write( "-7/7 - 12/7 = b\r<BR>\n" );
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document.write( "combine the fractions with the same denominator to get:\r<BR>\n" );
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document.write( "-17/7 = b\r<BR>\n" );
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document.write( "your new equation is y = (2/7)x - 17/7\r<BR>\n" );
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document.write( "once you know the slope, you can also solve for the equation by using the point slope form of the equation of a straight line.\r<BR>\n" );
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document.write( "that form is y-y1 = m(x-x1)\r<BR>\n" );
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document.write( "m is equal to (2/7)<BR>\n" );
document.write( "y1 is equal to -1<BR>\n" );
document.write( "x is equal to 6\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "y + 1 = (2/7)(x-6)\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "y + 1 = (2/7)x - 12/7\r<BR>\n" );
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document.write( "subtract 1 from both sides of the equation to get:\r<BR>\n" );
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document.write( "y = (2/7)x - 12/7 - 1\r<BR>\n" );
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document.write( "since -1 is equivalent to -7/7, you get:\r<BR>\n" );
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document.write( "y = (2/7)x - 12/7 - 7/7 which results in:\r<BR>\n" );
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document.write( "y = (2/7)x - 17/7\r<BR>\n" );
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document.write( "that's your equation.\r<BR>\n" );
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document.write( "a graph of your equation and the original equation of y = (2/7)x + 3 is shown below:\r<BR>\n" );
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document.write( "as you can see, the lines are parallel and the bottom line goes through the point (6,-1). </SPAN>\n" );
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