document.write( "Question 884052: 5a+3b=11
\n" ); document.write( "-2a+3=b\r
\n" ); document.write( "\n" ); document.write( "What is the value of b for the solution
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Algebra.Com's Answer #533958 by cigany29(23)\"\" \"About 
You can put this solution on YOUR website!
You are told that b=-2a+3
\n" ); document.write( "f(x)=5a+3b=11
\n" ); document.write( "g(x)=-2a+3\r
\n" ); document.write( "\n" ); document.write( "\"%28fog%29%28x%29=5a%2B3%28-2a%2B3%29=11\"\r
\n" ); document.write( "\n" ); document.write( "So in your first equation, substitute -2a+3 for b.\r
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\n" ); document.write( "\n" ); document.write( "\"5a%2B3b=11\"
\n" ); document.write( "\"5a%2B3%28-2a%2B3%29=11\"
\n" ); document.write( "\"5a-6a%2B9=11\"
\n" ); document.write( "\"-a%2B9=11\"
\n" ); document.write( "\"-a=2\"
\n" ); document.write( "\"a=-2\"\r
\n" ); document.write( "\n" ); document.write( "Now sub your found value of a into the equation to find b.\r
\n" ); document.write( "\n" ); document.write( "\"b=-2a%2B3\"
\n" ); document.write( "\"b=-2%28-2%29%2B3\"
\n" ); document.write( "\"b=4%2B3\"
\n" ); document.write( "\"b=7\"\r
\n" ); document.write( "\n" ); document.write( "You can check this by substituting your values for a and b back into your first equation\r
\n" ); document.write( "\n" ); document.write( "\"5a%2B3b=11\"
\n" ); document.write( "\"5%28-2%29%2B3%287%29=11\"
\n" ); document.write( "\"-10%2B21=11\"
\n" ); document.write( "\"11=11\"
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