document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883974>Question 883974</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a certain amount of money is invested at 3% per year, and 1500 more than that amount is invested at 5% per year. The annual interest from the 5% investment exceeds the annual interest from the 3% investment by 125. How much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533899 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a certain amount of money is invested at 3% per year, and 1500 more than that amount is invested at 5% per year. The annual interest from the 5% investment exceeds the annual interest from the 3% investment by 125. How much is invested at each rate?<BR>\n" );
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document.write( "let x=amt invested at 3%<BR>\n" );
document.write( "x+1500=amt invested at 5%<BR>\n" );
document.write( "..<BR>\n" );
document.write( "5%(x+1500)-3%x=125<BR>\n" );
document.write( ".05x+75-.03x=125<BR>\n" );
document.write( ".02x=50<BR>\n" );
document.write( "x=2500<BR>\n" );
document.write( "x+1500=4000<BR>\n" );
document.write( "amt invested at 3%=$2500<BR>\n" );
document.write( "amt invested at 5%=$4000 </SPAN>\n" );
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