document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883883>Question 883883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> cosx=12/20 quadrant IV find values to cos2x sin2x and tan2x<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533883 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cosx=12/20 quadrant IV find values to cos2x sin2x and tan2x<BR>\n" );
document.write( "***<BR>\n" );
document.write( "cosx=12/20=3/5 (working with a (3-4-5) reference right triangle in quadrant IV)<BR>\n" );
document.write( "sinx=-4/5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "cos 2x=cos^2x-sin^2x=9/25-16/25=-7/25<BR>\n" );
document.write( "sin2x=2sinxcosx=2*-4/5*3/5=-24/25<BR>\n" );
document.write( "tan2x=sin2x/cos2x=24/7 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );