document.write( "Question 883918: A boat travels 30 miles upstream in three hours. It makes the return trip in one and a half hours. What is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #533866 by josmiceli(19441)\"\" \"About 
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Let \"+s+\" = the speed of the boat in still water
\n" ); document.write( "Let \"+c+\" = the speed of the current
\n" ); document.write( "------------------
\n" ); document.write( "Going upstream:
\n" ); document.write( "(1) \"+30+=+%28+s+-+c+%29%2A3+\"
\n" ); document.write( "Going downstream:
\n" ); document.write( "(2) \"+30+=+%28+s+%2B+c+%29%2A1.5+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+3s+-+3c+=+30+\"
\n" ); document.write( "(2) \"+1.5s+%2B+1.5c+=+30+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+s+-+c+=+10+\"
\n" ); document.write( "(2) \"+15s+%2B+15c+=+300+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "Multiply both sides of (1) by \"+15+\"
\n" ); document.write( "and add the equations
\n" ); document.write( "(1) \"+15s+-+15c+=+150+\"
\n" ); document.write( "(2) \"+15s+%2B+15c+=+300+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "\"+30s+=+450+\"
\n" ); document.write( "\"+s+=+15+\"
\n" ); document.write( "------------
\n" ); document.write( "The speed of the boat in still water is 15 mi/hr
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+s+-+c+=+10+\"
\n" ); document.write( "(1) \"+15+-+c+=+10+\"
\n" ); document.write( "(1) \"+c+=+5+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+30+=+%28+s+%2B+c+%29%2A1.5+\"
\n" ); document.write( "(2) \"+30+=+%28+15+%2B+5+%29%2A1.5+\"
\n" ); document.write( "(2) \"+30+=+20%2A1.5+\"
\n" ); document.write( "(2) \"+30+=+30+\"
\n" ); document.write( "OK\r
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