document.write( "Question 883812: An ocean liner was sailing from New
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document.write( "York to London at 20 miles per hour.
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document.write( "A slower ocean liner was also sailing
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document.write( "from New York to London and left the
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document.write( "same time as the first ocean liner. After
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document.write( "sailing for 40 hours, the two ocean liners were a distance of 200 miles from
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document.write( "each other. What was the slower ocean
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document.write( "liner’s speed?\r
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document.write( "Can you please explain how to solve....Thanks a lot \n" );
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Algebra.Com's Answer #533824 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! ocean liners rate is 20 miles per hour \n" ); document.write( "slower ocean liners rate is x \n" ); document.write( "after 40 hours, \n" ); document.write( "ocean liner has covered 20*40 = 800 miles \n" ); document.write( "slower ocean liner has covered 600 miles ( 800 - 200), therefore \n" ); document.write( "40x = 600 \n" ); document.write( "x = 15 \n" ); document.write( "the rate of the slower ocean liner is 15 miles per hour\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |