document.write( "Question 883840: I need help solving this the sum of twice a number and three is greater than forty nine\r
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Algebra.Com's Answer #533808 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let the unknown number = \"+n+\"
\n" ); document.write( "given:
\n" ); document.write( "\"+2n+%2B+3+%3E+49+\"
\n" ); document.write( "Subtract \"+3+\" from both sides
\n" ); document.write( "\"+2n+%3E+46+\"
\n" ); document.write( "Divide both sides by \"+2+\"
\n" ); document.write( "\"+n+%3E+23+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "You can check this by first letting
\n" ); document.write( "\"+n+=+23+\"
\n" ); document.write( "\"+2n+%2B+3+%3E+49+\"
\n" ); document.write( "\"+2%2A23+%2B+3+%3E+49+\"
\n" ); document.write( "\"+49+%3E+49+\" not true
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\n" ); document.write( "Next let \"+n+=+24+\"
\n" ); document.write( "\"+2%2A24+%2B+3+%3E+49+\"
\n" ); document.write( "\"+51+%3E+49+\" true
\n" ); document.write( "So, the answer looks correct
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