document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883840>Question 883840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this the sum of twice a number and three is greater than forty nine\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533807 by </B><A HREF=/tutors/aboutme.mpl?userid=montecristo73><B>montecristo73(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=montecristo73><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There is a number here which we don't know, so we will call it x.\r<BR>\n" );
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document.write( "Twice that number is the same as saying 2x.\r<BR>\n" );
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document.write( "So... 2x + 3 > 49\r<BR>\n" );
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document.write( "Now we solve as if it was an equation. We add -3 to both sides and we get...\r<BR>\n" );
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document.write( "2x > 46\r<BR>\n" );
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document.write( "We divide both sides by 2 to isolate x...\r<BR>\n" );
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document.write( "x > 23\r<BR>\n" );
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document.write( "There you go. Any number greater than 23 is a correct answer to your problem. Let's verify by substituting x for 24.\r<BR>\n" );
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document.write( "2(24) + 3 > 49\r<BR>\n" );
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document.write( "48 + 3 > 49\r<BR>\n" );
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document.write( "51 > 49\r<BR>\n" );
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document.write( "Yep! It checks! </SPAN>\n" );
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