document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883839>Question 883839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a circle with a diameter of 12 centimeters, find the area of a sector whose central area has the following measure.\r<BR>\n" );
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document.write( "40  A=\r<BR>\n" );
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document.write( "120  A= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533792 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a circle with a diameter of 12 centimeters, find the area of a sector whose central area has the following measure.<BR>\n" );
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document.write( "The area of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2+=+36pi ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2+=+36pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The area of a sector of angle A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=36pi+%2A+A%2F360 ALIGN=MIDDLE  ALT=\"36pi+%2A+A%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" > (A in degrees) </SPAN>\n" );
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