document.write( "Question 883766: The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 30 and the common ratio is two fifths. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population. \r
\n" ); document.write( "\n" ); document.write( " a)the summation of 30 times two fifths to the i minus 1 power, from i equals 1 to infinity.; the sum is 50. \r
\n" ); document.write( "\n" ); document.write( " b)the summation of 30 times two fifths to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent. \r
\n" ); document.write( "\n" ); document.write( " c)the summation of two fifths times 30 to the i minus 1 power, from i equals 1 to infinity.; the sum is 50. \r
\n" ); document.write( "\n" ); document.write( " d)the summation of two fifths times 30 to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent.
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Algebra.Com's Answer #533766 by jim_thompson5910(35256)\"\" \"About 
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S = a/(1 - r)\r
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\n" ); document.write( "\n" ); document.write( "S = 30/(1 - 2/5)\r
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\n" ); document.write( "\n" ); document.write( "S = 50\r
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\n" ); document.write( "\n" ); document.write( "So the sum is 50.\r
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\n" ); document.write( "\n" ); document.write( "The sigma notation is \r
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\n" ); document.write( "\n" ); document.write( "So the answer is choice a)\r
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\n" ); document.write( "\n" ); document.write( "a)the summation of 30 times two fifths to the i minus 1 power, from i equals 1 to infinity.; the sum is 50.
\n" ); document.write( "b)the summation of 30 times two fifths to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent.
\n" ); document.write( "c)the summation of two fifths times 30 to the i minus 1 power, from i equals 1 to infinity.; the sum is 50.
\n" ); document.write( "d)the summation of two fifths times 30 to the i minus 1 power, from i equals 1 to infinity.; the sum is divergent.
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