document.write( "Question 883743: Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?\r
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document.write( "1 liter milk
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document.write( "1 liter water
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document.write( "2 liters milk
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document.write( "1.5 liter milk
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document.write( "3 Liter milk \n" );
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Algebra.Com's Answer #533760 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! The description feels clumsy. Fraction concentration volume for volume seem more neat to use, for me, anyway.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The milk mixture needed was to be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Milk Mixture wanted: 6/10. \n" ); document.write( "Milk Mixture received: 5/10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add some milk, v liters, to the 8 liters of less concentrated mixture.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Form this equation (as the reasoning for it is omitted): \n" ); document.write( " \n" ); document.write( "and simplification should be performed \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |