document.write( "Question 883743: Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?\r
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\n" ); document.write( "1 liter water
\n" ); document.write( "2 liters milk
\n" ); document.write( "1.5 liter milk
\n" ); document.write( "3 Liter milk
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Algebra.Com's Answer #533760 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
The description feels clumsy. Fraction concentration volume for volume seem more neat to use, for me, anyway.\r
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\n" ); document.write( "\n" ); document.write( "The milk mixture needed was to be \"3%2F5\" milk in water. What was actually delivered was 8 liters of \"2.5%2F5\" milk in water. Maybe one would not like the use of rational looking numbers with non-integer part: Then we can also say,\r
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\n" ); document.write( "\n" ); document.write( "Milk Mixture wanted: 6/10.
\n" ); document.write( "Milk Mixture received: 5/10.\r
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\n" ); document.write( "\n" ); document.write( "Add some milk, v liters, to the 8 liters of less concentrated mixture.\r
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\n" ); document.write( "\n" ); document.write( "Form this equation (as the reasoning for it is omitted):
\n" ); document.write( "\"highlight_green%28highlight_green%28%288%285%2F10%29%2Bv%29%2F%28v%2B8%29=6%2F10%29%29\"
\n" ); document.write( "and simplification should be performed
\n" ); document.write( "\"%288%281%2F2%29%2Bv%29%2F%28v%2B8%29=3%2F5\"
\n" ); document.write( "\"%284%2Bv%29%2F%28v%2B8%29=3%2F5\"
\n" ); document.write( "\"5%284%2Bv%29=3%28v%2B8%29\"
\n" ); document.write( "\"5v%2B20=3v%2B24\"
\n" ); document.write( "\"2v=4\"
\n" ); document.write( "\"highlight%28v=2%29\" liters of milk to add.\r
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