document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883725>Question 883725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 99. if twice the smaller number is subtracted from the larger number, the result is 15 find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533719 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a = larger number<BR>\n" );
document.write( "Let b = smaller number<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "(1) a + b = 99 and<BR>\n" );
document.write( "(2) a - 2*b = 15 or<BR>\n" );
document.write( "(3) a = 15 + 2*b<BR>\n" );
document.write( "Put a of (3) into (1) to get<BR>\n" );
document.write( "(4) 15 + 2*b + b = 99 or<BR>\n" );
document.write( "(5) 3*b = 99 - 15 or<BR>\n" );
document.write( "(6) 3*b = 84 or<BR>\n" );
document.write( "(7) b = 28<BR>\n" );
document.write( "Then using (1) we get<BR>\n" );
document.write( "(8) a + 28 = 99 or<BR>\n" );
document.write( "(9) a = 71<BR>\n" );
document.write( "Check the answer with (2).<BR>\n" );
document.write( "Is (71 - 2*28 = 15)?<BR>\n" );
document.write( "Is (71 - 56 = 15)?<BR>\n" );
document.write( "Is (15 = 15)? Yes<BR>\n" );
document.write( "Answer: The two numbers are 71 and 28.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );