document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883725>Question 883725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 99. if twice the smaller number is subtracted from the larger number, the result is 15 find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533718 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + B = 99<BR>\n" );
document.write( "A - 2B = 15<BR>\n" );
document.write( "Use the second equation and add 2B to each side to get:<BR>\n" );
document.write( "A = 2B + 15<BR>\n" );
document.write( "Now substitute the value of A from that equation into the first equation:<BR>\n" );
document.write( "A + B = 99<BR>\n" );
document.write( "(2B + 15) + B = 99<BR>\n" );
document.write( "Add<BR>\n" );
document.write( "3B + 15 = 99<BR>\n" );
document.write( "Subtract 15 from each side<BR>\n" );
document.write( "3B = 84<BR>\n" );
document.write( "Divide each side by 3<BR>\n" );
document.write( "B = 28<BR>\n" );
document.write( "If B is 28, then A is 99-28, or 71<BR>\n" );
document.write( " </SPAN>\n" );
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