document.write( "Question 74272: Marivic is five years older than Michelle. In three years, the product of her age and Michelle's age five years ago will be 90 years. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #53371 by vidhyak(98)![]() ![]() ![]() You can put this solution on YOUR website! Let Marivic's age be x \n" ); document.write( "Let Michelle's age be y \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Marivic is five years older than Michelle \r \n" ); document.write( "\n" ); document.write( "x = y + 5 -----------------------eq. 1 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In three years, the product of her age and Michelle's age five years ago will be 90 years \r \n" ); document.write( "\n" ); document.write( "In three years marvic will be x + 3 yrs old \n" ); document.write( "Michelle's age five years ago was y - 5 yrs old \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x + 3)(y - 5) = 90 --------------eq 2 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitue eq1 in eq2 \r \n" ); document.write( "\n" ); document.write( "(y + 5 + 3) (y - 5) = 90 \n" ); document.write( "(y + 8) (y - 5) = 90 \n" ); document.write( "y^2 + 3y -40 = 90 \n" ); document.write( "y^2 + 3y -130 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answers for y= 10,-13\r \n" ); document.write( "\n" ); document.write( "Age is a positive integer, so Michelle's age is 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = y + 5 \n" ); document.write( "x= 15\r \n" ); document.write( "\n" ); document.write( "so Marivic's age is 15 \n" ); document.write( " \n" ); document.write( " |