document.write( "Question 883715: I am thinking of three counting numbers which have a product of 48. Also, one less than twice their sum is a perfect square. What are my numbers? \n" ); document.write( "
Algebra.Com's Answer #533708 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! You are thinking of (2,3,8). \n" ); document.write( "Their product is 48 and twice their sum less one is 25 - a perfect square. \n" ); document.write( "I found the answer by generating a list of possible sums of the three counting numbers given by \n" ); document.write( "(1) S = (n^2 + 1)/2 \n" ); document.write( "In order to get an integer sum, (n^2+1) must be even. Another constraint is that the sum must be greater than three and less than 51. \n" ); document.write( "Chosing n = (1,2,3... 11) we get those values of n that satisfy these two conditions \n" ); document.write( "(2) n = {3,5,7,9) giving the possible sum, S, of \n" ); document.write( "(3) S = {5,13,25,41} \n" ); document.write( "Now to select values of the three numbers a,b,c using the condition that their product is 48 and the their sum is an entry in (3). \n" ); document.write( "First let a = 1, then \n" ); document.write( "(4) b*c = 48 as given by the pairs \n" ); document.write( "(5) (b,c) = {(1,48),(2,24),(3,16),(4,12),(6,8)} which when added to a = 1 gives the sums \n" ); document.write( "(6) a+b+c = {50,27,20,17,15} \n" ); document.write( "None of the values of the sum given by (5) are equal to any of the possible sums given by (3). So try the next value of a = 2. Then \n" ); document.write( "(7) b*c = 24 as given by the pairs \n" ); document.write( "(8) (b,c) = {(1,24),(2,12),(3,8),(4,6)} which when added to a = 2 gives the sums \n" ); document.write( "(9) a+b+c = {27,16,13,12} \n" ); document.write( "Note that the sum of 13 in (9) is also an entry in (3), thus we have a solution \n" ); document.write( "(10) {a,b,c} = {2,3,8} QED\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |