document.write( "Question 883701: Find a number which is smaller then 100 that increases by 1 by 5th of its value when its digits are reversed \n" ); document.write( "
Algebra.Com's Answer #533700 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Find a number which is smaller then 100 that increases by 1/5th of its value when its digits are reversed \n" ); document.write( ": \n" ); document.write( "let a = the 10's digit \n" ); document.write( "let b = the units \n" ); document.write( ": \n" ); document.write( "To increase a value by 1/5, multiply it by 1.2 \n" ); document.write( ": \n" ); document.write( "1.2(10a+b) = 10b + a \n" ); document.write( "12a + 1.2b = 10b + a \n" ); document.write( "12a - a = 10b - 1.2b \n" ); document.write( "11a = 8.8b \n" ); document.write( "divide by 11 \n" ); document.write( "a = .8b \n" ); document.write( "Only one value for b gives a single digit integer \n" ); document.write( "b = 5,then \n" ); document.write( "a = .8(5) \n" ); document.write( "a = 4 \n" ); document.write( ": \n" ); document.write( "45 is the number \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check 54/45 = 1.2 \n" ); document.write( " |