document.write( "Question 883683: There are 15 people waiting to take their driver's training test. In how many ways can the 15 be divided equally among 3 examiners?\r
\n" ); document.write( "\n" ); document.write( "I know this is probably a combination problem so can you show me using the long way and the calculator? \n" ); document.write( "
Algebra.Com's Answer #533690 by pj66(7)\"\" \"About 
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The questions says we need to divide equally among 3 examiners. We will use combination formula - (n)C_r = (n!)/(r!*(n-r)!)
\n" ); document.write( "15 people are to be divided amongst 3 examiners i.e 5 people for each examiner.
\n" ); document.write( "for first examiner : (15)C_5 = 3036 ---------(1)
\n" ); document.write( "Because the first one can choose any five from pool of fifteen.
\n" ); document.write( "for second examiner : (10)C_5 = 252 ---------(2)
\n" ); document.write( "Because second examiner will have to choose 5 people from remaining 15.
\n" ); document.write( "for third examiner : (5)C_5 = 120 ---------(3)
\n" ); document.write( "Because third examiner will have the last five.\r
\n" ); document.write( "\n" ); document.write( "Number of ways in which 15 people can be chosen by 3 examiners we will multiply (1),(2) and (3) = 91808640\r
\n" ); document.write( "\n" ); document.write( "Let me know if you have any doubts and whether the answer is correct.
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