document.write( "Question 883651: Find the slope of the line bisecting the angle from line1, with slope 2, to line2, with no slope.\r
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Algebra.Com's Answer #533682 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You are only given slopes, so it must mean that y-intercepts do not matter.
\n" ); document.write( "The lines could intersect each other anywhere, and they could intersect the x- and y-axes anywhere,
\n" ); document.write( "but for convenience I will make the lines intersect at the origin.
\n" ); document.write( "(Whoever does not like my drawing can move the axes up, down, and left or right to his/her taste. As long as nothing is rotated, the slopes remain the same).
\n" ); document.write( " The slope of line 1 is the tangent of the angle \"red%28A%29%29\" it makes with the x-axis (measured counterclockwise from the positive x-axis).
\n" ); document.write( "The slope of the y-axis is undefined, and line 2 is the y-axis.
\n" ); document.write( "The bisector of the acute angle formed by lines 1 and 2 is drawn in green.
\n" ); document.write( "The angle it forms with the positive x-axis is
\n" ); document.write( "\"%28A%2B90%5Eo%29%2F2\"
\n" ); document.write( "(If you don't like degrees, it is \"%28A%2Bpi%2F2%29%2F2\" in radians).
\n" ); document.write( "The slope of the bisector is the tangent of that angle.
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\n" ); document.write( "If you only need an approximate value, you could use inverse trigonometric functions.
\n" ); document.write( "For an exact value, I would use trigonometric identities.
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\n" ); document.write( "USING INVERSE FUNCTIONS:
\n" ); document.write( "We use the inverse of tangent from calculator or computer to find the angle that has a tangent of \"2\".
\n" ); document.write( "Hopefully you know how to do that with your calculator and/or computer.
\n" ); document.write( "The inverse function of tangent is represented as \"%22tan%22%5E%28-1%29\" , or \"arctan\" , or \"ATAN\" , and in some calculators you have to press a key for inverse functions and then the tangent key.
\n" ); document.write( "\"tan%28A%29=2\"--->\"A=63.4%5Eo\"(rounded),
\n" ); document.write( "or \"A=1.107\"(rounded) in radians, if you prefer radians.
\n" ); document.write( "Using \"A=63.4%5Eo\":
\n" ); document.write( "\"%28A%2B90%5Eo%29%2F2=76.7%5Eo\" and \"tan%2876.7%5Eo%29=4.23\"(rounded) is the approximate value for the slope of the bisector.
\n" ); document.write( "Using \"A=1.107\"(in radians):
\n" ); document.write( "\"%281.107%2Bpi%2F2%29%2F2=1.339\"(rounding the result but not \"pi\" ), and
\n" ); document.write( "\"tan%281.339%29=4.24\"(rounded) is the approximate value for the slope of the bisector.
\n" ); document.write( "You could round to more digits to get a better approximation.
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\n" ); document.write( "USING TRIGONOMETRIC IDENTITIES FOR EXACT VALUE:
\n" ); document.write( "From the values of the trigonometric functions for \"A\",
\n" ); document.write( "and the well known values for \"90%5Eo=pi.2\" ,
\n" ); document.write( "we would like to find the trigonometric functions for \"%28A%2B90%5Eo%29%2F2=%28A%2Bpi%2F2%29%2F2\" .
\n" ); document.write( "For easier typing, I am going to use \"90%5Eo+rather+%7B%7B%7Bpi%2F2\" from now on.
\n" ); document.write( "There are probably many ways to get to \"tan%28%28A%2B90%5Eo%29%2F2%29\" ,
\n" ); document.write( "but I am going to show the one that came to my mind first,
\n" ); document.write( "and that requires starting from \"sin%28A%29\" and \"cos%28A%29\" .
\n" ); document.write( "The right triangle with angle \"A\" that I included in my sketch
\n" ); document.write( "has legs measuring \"1\" and \"2\" ,
\n" ); document.write( "so the Pythagorean theorem says that the length of the hypotenuse is \"sqrt%281%5E2%2B2%5E2%29=sqrt%281%2B4%29=sqrt%285%29\" .
\n" ); document.write( "Trigonometric ratios tell us that
\n" ); document.write( "\"sin%28A%29=2%2Fsqrt%285%29\" and \"cos%28A%29=1%2Fsqrt%285%29\"
\n" ); document.write( "Trigonometric identities for sum of angles tell us that
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\n" ); document.write( "We are half of he way there
\n" ); document.write( "Trigonometric identities for half angles are
\n" ); document.write( "\"abs%28sin%28B%2F2%29%29=sqrt%28%281-cos%28B%29%29%2F2%29\" and \"abs%28cos%28B%2F2%29%29=sqrt%28%281%2Bcos%28B%29%29%2F2%29\" ,
\n" ); document.write( "and we have to figure out the sign for ourselves.
\n" ); document.write( "Since \"%28A%2B90%5Eo%29%2F2\" is in the first quadrant, we know that all its trigonometric functions have positive values, so
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\n" ); document.write( "Tangent is sine divided by cosine, so
\n" ); document.write( "==\"sqrt%28%28sqrt%285%29%2B2%29%5E2%2F%28%28sqrt%285%29%2B2%29%28sqrt%285%29-2%29%29%29\"=\"sqrt%28%28sqrt%285%29%2B2%29%5E2%2F%285-2%5E2%29%29\"=\"sqrt%28%28sqrt%285%29%2B2%29%5E2%2F%285-4%29%29\"=\"sqrt%28%28sqrt%285%29%2B2%29%5E2%29\"=\"highlight%28sqrt%285%29%2B2%29\"
\n" ); document.write( "The approximate value of \"sqrt%285%29%2B2\" is \"4.236\" .
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