document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883631>Question 883631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ednpoint of a diameter of a circle is (-1,6). If the center is at (2,-1), find the other endpoint of the diameter passing through (-1,6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533653 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the radius using Distance Formula for points (-1,6) and the center(2,-1)....\r<BR>\n" );
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document.write( "There is an alternative.  The center and the given endpoint form a line.  The other endpoint is a point on this line.  Now, using Distance formula, and knowing the equation of this line, you are looking for the point this way:\r<BR>\n" );
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document.write( "D, (-1,6) to (2,-1) SAME AS  D, (x,y) to (2,-1).  \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%286-%28-1%29%29%5E2%2B%28-1-2%29%5E2%29=sqrt%28%28x-2%29%5E2%2B%28y-%28-1%29%29%5E2%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%2849%29%5E2%2B%289%29%5E2%29=sqrt%28%28x-2%29%5E2%2B%28y%2B1%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%2849%29%5E2%2B%289%29%5E2%29=sqrt%28%28x-2%29%5E2%2B%28y%2B1%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28130%29=sqrt%28x-2%29%5E2%2B%28y%2B1%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28130%29=sqrt%28x-2%29%5E2%2B%28y%2B1%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=130=%28x-2%29%5E2%2B%28y%2B1%29%5E2 ALIGN=MIDDLE  ALT=\"130=%28x-2%29%5E2%2B%28y%2B1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >---actually this is just the equation of the circle.\r<BR>\n" );
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document.write( "The line containing given endpoint and circle center:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=%286%2B1%29%2F%28-3%29 ALIGN=MIDDLE  ALT=\"m=%286%2B1%29%2F%28-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=-7%2F3 ALIGN=MIDDLE  ALT=\"m=-7%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "y=mx+b<BR>\n" );
document.write( "b=y-mx<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=-1-%28-7%2F3%29%2A2 ALIGN=MIDDLE  ALT=\"b=-1-%28-7%2F3%29%2A2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1-%28-14%2F3%29 ALIGN=MIDDLE  ALT=\"-1-%28-14%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14%2F3-3%2F3 ALIGN=MIDDLE  ALT=\"14%2F3-3%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=11%2F3 ALIGN=MIDDLE  ALT=\"b=11%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y=-%287%2F3%29x%2B11%2F3%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y=-%287%2F3%29x%2B11%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "WHAT NEXT TO DO?<BR>\n" );
document.write( "Substitute for y in the circle equation, simplify, and solve for x.  You will get two values.  The one you are looking for is the solution OTHER THAN x=-1.  Now, use it to find y. </SPAN>\n" );
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