document.write( "Question 883590: What is the trick to solving this problem how do we know what number to multiply by to cancel out the X.
\n" ); document.write( "8X-7Y=-51
\n" ); document.write( "12X+13Y=41
\n" ); document.write( " We are not sure how to come up with the number to break it down
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Algebra.Com's Answer #533620 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"8x-7y=-51\"...........eq.1
\n" ); document.write( "\"12x%2B13y=41\"..........eq.2
\n" ); document.write( "___________________________\r
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\n" ); document.write( "\n" ); document.write( "how do we know what number to multiply by to cancel out the \"x\": \r
\n" ); document.write( "\n" ); document.write( "first look what are coefficients of the \"x\" in eq.1 and eq.2, you see these are \"8\" and \"12\"
\n" ); document.write( "now, you know that \"24\" is divisible by \"8\" and by \"12\"; so make it as common coefficients of the \"x\" in eq.1 and eq.2\r
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\n" ); document.write( "\n" ); document.write( "\"8x-7y=-51\"...........eq.1.............multiply by \"3\"
\n" ); document.write( "\"12x%2B13y=41\"..........eq.2.............multiply by \"2\"
\n" ); document.write( "___________________________\r
\n" ); document.write( "\n" ); document.write( "\"24x-21y=-153\"...........eq.1
\n" ); document.write( "\"24x%2B26y=82\"..........eq.2
\n" ); document.write( "___________________________...............now subtract eq.2 from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"24x-21y=-153\"...........eq.1
\n" ); document.write( "-
\n" ); document.write( "\"24x%2B26y=82\"..........eq.2
\n" ); document.write( "_________________________________\r
\n" ); document.write( "\n" ); document.write( "\"cross%2824x%29-cross%2824x%29-21y-26y=-153-82\"\r
\n" ); document.write( "\n" ); document.write( "\"-47y=-235\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-235%2F-47\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=5%29\"\r
\n" ); document.write( "\n" ); document.write( "now, go back to eq.1, plug in \"y=5\" and solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"8x-7%2A5=-51\"...........eq.1\r
\n" ); document.write( "\n" ); document.write( "\"8x-35=-51\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=-51%2B35\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=-16\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-16%2F8\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=-2%29\"\r
\n" ); document.write( "\n" ); document.write( "see it on a graph:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+8x%2F7%2B51%2F7%2C+-12x%2F13%2B41%2F13%29+\"\r
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