document.write( "Question 883491: solve for y in the equation
\n" ); document.write( "3/x - 4/y + 6/z = 1
\n" ); document.write( "9/x + 8/y - 12/z = 3
\n" ); document.write( "9/x - 4/y + 12/z = 4
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Algebra.Com's Answer #533612 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
It is easy to solve the system if we make
\n" ); document.write( "\"a=1%2Fx\", \"b=1%2Fy\" , and \"c=1%2Fz\"
\n" ); document.write( "After that, we just write
\n" ); document.write( "\"system%283a-4b%2B6c=1%2C9a%2B8b-a2c=3%2C9a-4b%2B12c=4%29\" and solve for \"b\" .
\n" ); document.write( "Multiplying the first equation times 2 and adding the second equation we get
\n" ); document.write( "\"6a-8b%2B12c=2\"
\n" ); document.write( "\"9a%2B8b-12c=3\"
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\n" ); document.write( "\"15a=5\" ----> \"a=5%2F15\" ---> \"a=1%2F3\"
\n" ); document.write( "Adding the second and third equations we get
\n" ); document.write( "\"6a-8b%2B12c=2\"
\n" ); document.write( "\"9a-4b%2B12c=4\"
\n" ); document.write( "_________________
\n" ); document.write( "\"18a%2B4b=7\"
\n" ); document.write( "With the two resulting equations without a \"c\" , we solve for \"b\"
\n" ); document.write( "\"system%28a=1%2F3%2C18a%2B4b=7%29\" ---> \"18%2A%281%2F3%29%2B4b=7\"-->\"6%2B4b=7\"-->\"4b=7-6\"-->\"4b=1\"-->\"b=1%2F4\"
\n" ); document.write( "So, \"system%28b=1%2Fy%2Cb=1%2F4%29\" ---> \"highlight%28b=4%29\" ---> \"highlight%28y=1%2F4%29\"
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