document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883470>Question 883470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 120 and one of the number is 3 times the other. find the value of the numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533556 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + B = 120<BR>\n" );
document.write( "A = 3B<BR>\n" );
document.write( "Substitute the value of A from the second equation into the first.<BR>\n" );
document.write( "(3B) + B = 120<BR>\n" );
document.write( "4B = 120<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "B = 30 </SPAN>\n" );
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