document.write( "Question 883428: What is the center of an ellipse 16x^2+64x+y^2-4y+4=0
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Algebra.Com's Answer #533550 by lwsshak3(11628) $\"\"$ $\"About$

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What is the center of an ellipse
\n" ); document.write( "16x^2+64x+y^2-4y+4=0
\n" ); document.write( "complete the square:
\n" ); document.write( "16(x^2+4x+4)+(y^2-4y+4)=-4+64+4
\n" ); document.write( "16(x+2)^2+(y-2)^2=64
\n" ); document.write( "(x+2)^2/4+(y-2)^2/64=1
\n" ); document.write( "This is an equation of an ellipse with vertical major axis.
\n" ); document.write( "Its standard form of equation: $\"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\"$ , (h,k)=coordinates of center
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (-2,2) \n" ); document.write( "

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