document.write( "Question 883299: It would be greatly appreciated if you are able to help me with:\r
\n" ); document.write( "\n" ); document.write( "Johnathan drove to the airport to pick up his friend. A rainstorm forced him to drive at an average speed of 45 mph, reaching the airport in 3 hours. He drove back home at an average speed of 55 mph. How long, to the nearest tenth of an hour, did the trip home take him?\r
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Algebra.Com's Answer #533430 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Johnathan drove to the airport to pick up his friend.
\n" ); document.write( "A rainstorm forced him to drive at an average speed of 45 mph, reaching the airport in 3 hours.
\n" ); document.write( "Note: distance to the airport = rate*time = 45 mph * 3 hr = 135 miles
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\n" ); document.write( "\n" ); document.write( "He drove back home at an average speed of 55 mph. How long, to the nearest tenth of an hour, did the trip home take him?
\n" ); document.write( "Equation:
\n" ); document.write( "time = distance/rate = 135 mi / 55 mph = 2.45 hrs = 2hr 33 minutes
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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