document.write( "Question 883247: factor completely. if a polynomial is prime , state this.
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Algebra.Com's Answer #533400 by jim_thompson5910(35256) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Looking at the expression $\"10a%5E2-11a%2B3\"$ , we can see that the first coefficient is $\"10\"$ , the second coefficient is $\"-11\"$ , and the last term is $\"3\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient $\"10\"$ by the last term $\"3\"$ to get $\"%2810%29%283%29=30\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to $\"30\"$ (the previous product) and add to the second coefficient $\"-11\"$ ?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of $\"30\"$ (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of $\"30\"$ :\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to $\"30\"$ .\r
\n" ); document.write( "\n" ); document.write( "1*30 = 30
\n" ); document.write( "2*15 = 30
\n" ); document.write( "3*10 = 30
\n" ); document.write( "5*6 = 30
\n" ); document.write( "(-1)*(-30) = 30
\n" ); document.write( "(-2)*(-15) = 30
\n" ); document.write( "(-3)*(-10) = 30
\n" ); document.write( "(-5)*(-6) = 30\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient $\"-11\"$ :\r
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First Number	Second Number	Sum
1	30	1+30=31
2	15	2+15=17
3	10	3+10=13
5	6	5+6=11
-1	-30	-1+(-30)=-31
-2	-15	-2+(-15)=-17
-3	-10	-3+(-10)=-13
-5	-6	-5+(-6)=-11

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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers $\"-5\"$ and $\"-6\"$ add to $\"-11\"$ (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers $\"-5\"$ and $\"-6\"$ both multiply to $\"30\"$ and add to $\"-11\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term $\"-11a\"$ with $\"-5a-6a\"$ . Remember, $\"-5\"$ and $\"-6\"$ add to $\"-11\"$ . So this shows us that $\"-5a-6a=-11a\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"10a%5E2%2Bhighlight%28-5a-6a%29%2B3\"$ Replace the second term $\"-11a\"$ with $\"-5a-6a\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%2810a%5E2-5a%29%2B%28-6a%2B3%29\"$ Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( " $\"5a%282a-1%29%2B%28-6a%2B3%29\"$ Factor out the GCF $\"5a\"$ from the first group.\r
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\n" ); document.write( "\n" ); document.write( " $\"5a%282a-1%29-3%282a-1%29\"$ Factor out $\"3\"$ from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( " $\"%285a-3%29%282a-1%29\"$ Combine like terms. Or factor out the common term $\"2a-1\"$ \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So $\"10a%5E2-11a%2B3\"$ factors to $\"%285a-3%29%282a-1%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"10a%5E2-11a%2B3=%285a-3%29%282a-1%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding $\"%285a-3%29%282a-1%29\"$ to get $\"10a%5E2-11a%2B3\"$ or by graphing the original expression and the answer (the two graphs should be identical).
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