document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882975>Question 882975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a half angle identity to find the value of tan 22° 30'. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533352 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use a half angle identity to find the value of tan 22° 30'.<BR>\n" );
document.write( "22&#730;30'=22.5&#730;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan+22.5=tan+%2845%2F2%29=sin+45%2F%281%2Bcos+45%29=%28sqrt%282%29%2F2%29%2F%281%2Bsqrt%282%29%2F2%29%0D%0A=%28sqrt%282%29%2F2%29%2F%28%282%2Bsqrt%282%29%29%2F2%29=%28sqrt%282%29%29%2F%282%2Bsqrt%282%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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