document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883099>Question 883099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a new rectangular is 3 yards longer then quadruple the width. if the perimeter is 606 what is the dimensions.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533340 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "4x + 3 = length {three yards longer than quadruple the width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2x + 2(4x + 3) = 606 {substituted width and length into perimeter formula}<BR>\n" );
document.write( "2x + 8x + 6 = 606 {used distributive property}<BR>\n" );
document.write( "10x + 6 = 606 {combined like terms}<BR>\n" );
document.write( "10x = 600 {subtracted 6 from each side}<BR>\n" );
document.write( "x = 60 {divided each side by 10}<BR>\n" );
document.write( "4x + 3 = 243 {substituted 60, in for x, into 4x + 3}\r<BR>\n" );
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document.write( "width = 60 yds<BR>\n" );
document.write( "length = 243 yds<BR>\n" );
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