document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883096>Question 883096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of rectangle is three times its width, with a perimeter of 80 cm, solve for the rectangles area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533337 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533337\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = P<BR>\n" );
document.write( "2L + 2W = 80<BR>\n" );
document.write( "L = 3W<BR>\n" );
document.write( "Substitute the known value of L from the last equation into the first.<BR>\n" );
document.write( "2(3W) + 2W = 80<BR>\n" );
document.write( "6W + 2W = 80<BR>\n" );
document.write( "8W = 80<BR>\n" );
document.write( "Divide each side by 8<BR>\n" );
document.write( "W = 10<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If the width is 10, then the length is 3x that, or 30<BR>\n" );
document.write( "Area = length * width<BR>\n" );
document.write( "A = 10 * 30<BR>\n" );
document.write( "Area = 300 square cm </SPAN>\n" );
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