document.write( "Question 883062: A 40 inch board is to be cut into 3 pieces so that the second piece is twice as long as the first piece, and the third piece is 5 times as long as the first piece. If x represents the length of the first piece, find the lengths of all three pieces. So I did: 40= x+2x+5x - 40=8x - (40/8=5) x=5? I don't know if that is correct. \n" ); document.write( "
Algebra.Com's Answer #533301 by algebrapro18(249)![]() ![]() ![]() You can put this solution on YOUR website! Well if we let the length of the first piece be x then the second piece would be 2x and the third piece would be 5x. \n" ); document.write( " \n" ); document.write( "So adding all the pieces together we get: \n" ); document.write( " \n" ); document.write( "5x+2x+x = 40 \n" ); document.write( " \n" ); document.write( "Now simplify and solve for x: \n" ); document.write( " \n" ); document.write( "5x+2x+x = 40 \n" ); document.write( "8x = 40 \n" ); document.write( "x = 5 \n" ); document.write( " \n" ); document.write( "So we know the shortest side is 5 inches. Plugging that into the other two sides we get side to being 10 inches(2*5) and the third side is 25 inches(5*5). So you had it right! \n" ); document.write( " |