document.write( "Question 9902: If 20 percent of nitrogen combined with the other elements. If 740 kg of nitrogen did not combine, how much did combine? \n" ); document.write( "

Algebra.Com's Answer #5333 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
NOTE: See last paragraph first. It's probably easier!! R^2\r
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\n" ); document.write( "\n" ); document.write( "I think it might be a good idea to set up a ratio, using this information: If 20% (i.e., .20) combines, then 80% (i.e., .80) does NOT comine. Let x = amount that combines, which is what you need to find.\r
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\n" ); document.write( "\n" ); document.write( " $\"+%28combined%29%2F%28not_combined%29\"$ : $\".20%2F.80+=+x%2F740\"$ \r
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\n" ); document.write( "\n" ); document.write( "Remember $\"a%2Fb=c%2Fd\"$ means that $\"a%2Ad=b%2Ac\"$ , so
\n" ); document.write( " $\".20%2F.80+=+x%2F740+\"$ \r
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\n" ); document.write( "\n" ); document.write( "This reduces to $\"1%2F4+=+x%2F740\"$ which means that
\n" ); document.write( " $\"4x+=+740\"$
\n" ); document.write( " $\"x=740%2F4\"$
\n" ); document.write( " $\"x=+185\"$ kg \r
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\n" ); document.write( "\n" ); document.write( "Now that I think about this, there is probably an easier way to do this, like just realizing that for every part that combines there are 4 parts that do not combine. Therefore, the amount that combines is 1/4 of the amount that does not combine, and 1/4 of 740 = 185 kg. That would have been a lot easier. Oh well. Too late now.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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