document.write( "Question 882939: Solve: \"x%5E2-2x-15%3C0\" \n" ); document.write( "
Algebra.Com's Answer #533284 by LinnW(1048)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2-2x-15%3C0\"
\n" ); document.write( "first solve
\n" ); document.write( " \"x%5E2-2x-15=0\"
\n" ); document.write( "\"%28x-5%29%2A%28x%2B2%29=0\"
\n" ); document.write( "x = 5 or x = -2
\n" ); document.write( "So for values of x between -2 and 5,
\n" ); document.write( "x^2-2x-15 is less than zero
\n" ); document.write( "(-2,5) is our solution
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