document.write( "Question 882997: the perimeter of a triangle is 42 inches. the second side is 1 inch more than twice the first side, and the third side is 1 inch less than three times the first side. Find the lengths of the three sides of the triangle.
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Algebra.Com's Answer #533258 by Leaf W.(135)![]() ![]() You can put this solution on YOUR website! Hello! \n" ); document.write( "*** \n" ); document.write( "Let us call the first side x. \n" ); document.write( "Since \"the second side is 1 inch more than twice the first side,\" we can represent the second side as 2x + 1 \n" ); document.write( "Since \"the third side is 1 inch less than three times the first side,\" we can represent the third side as 3x - 1 \n" ); document.write( "*** \n" ); document.write( "The perimeter of the triangle is 42 inches, so we can create the following equation: \n" ); document.write( "first side + second side + third side = 42 \n" ); document.write( "x + (2x + 1) + (3x - 1) = 42 \n" ); document.write( "*** \n" ); document.write( "Now, just simplify and solve for x! \n" ); document.write( "x + 2x + 1 + 3x - 1 = 42 \n" ); document.write( "Add like terms: 6x + 0 = 42 \n" ); document.write( "6x = 42 \n" ); document.write( "Divide both sides by 6: x = 7 \n" ); document.write( "*** \n" ); document.write( "Therefore, the length of the first side is 7 inches. Thus, the second side is 2x + 1 = 2(7) + 1 = 14 + 1 = 15 inches, and the third side is 3x - 1 = 3(7) - 1 = 21 - 1 = 20 inches. \n" ); document.write( "**** \n" ); document.write( "The three sides of the triangle must then be 7 inches, 15 inches, and 20 inches. \n" ); document.write( "I hope this helps! =) \n" ); document.write( " |