document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=883012>Question 883012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of 4% acid must be added to 10%acid to get 50ml of 8% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533243 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much of 4% acid must be added to 10%acid to get 50ml of 8% acid?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.04x + 0.10(50-x) = 0.08*50<BR>\n" );
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document.write( "4x + 10*50 - 10x = 8*50<BR>\n" );
document.write( "-6x = -2*50<BR>\n" );
document.write( "x = (1/3)50 = 16 2/3 ml (amt. of 4% solution needed)<BR>\n" );
document.write( "50-x = 33 1/3 ml (amt of 10% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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