document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882734>Question 882734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of secC^2-tanC^2 if sinC=12/13 and the terminal side of angle C is in quadrant two. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533201 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of secC^2-tanC^2 if sinC=12/13 and the terminal side of angle C is in quadrant two.<BR>\n" );
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document.write( "Note: since sin^2 + cos^2 = 1,<BR>\n" );
document.write( "dividing by cos^2 you get,<BR>\n" );
document.write( "tan^2 + 1 = sec^2<BR>\n" );
document.write( "So, sec^2 - tan^2 = 1<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "sec^2(C) - tan^2(C) = 1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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