document.write( "Question 882917: Pliz help me\r
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document.write( "A number is divided into 2 parts in such a way that 80% of the first part is 3 more than 60% of the 2nd part and 80% of the 2nd part is 6 more than 90% of the first part,find the number. (Answer is 135) \n" );
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Algebra.Com's Answer #533177 by rothauserc(4718) You can put this solution on YOUR website! Let x be the first part and y be the second part, then \n" ); document.write( ".8x = .6y + 3 \n" ); document.write( ".8y = .9x + 6 \n" ); document.write( "Solve for y in second equation \n" ); document.write( "y = .9x/.8 + 6/.8 \n" ); document.write( "y = 1.125x + 7.5 \n" ); document.write( "Substitute for y in first equation \n" ); document.write( ".8x = .6*(1.125x +7.5) + 3 \n" ); document.write( ".8x = 0.675x +7.5 \n" ); document.write( "0.125x = 7.5 \n" ); document.write( "x = 60 \n" ); document.write( "Now use first equation to determine y \n" ); document.write( "48 = .6y +3 \n" ); document.write( ".6y = 45 \n" ); document.write( "y = 75 \n" ); document.write( "First part is 60 and second part is 75 \n" ); document.write( "Check answers \n" ); document.write( ".8(60) = .6(75) + 3 \n" ); document.write( "48 = 45 + 3 \n" ); document.write( "48 = 48 \n" ); document.write( ".8(75) = .9(60) + 6 \n" ); document.write( "60 = 54 + 6 \n" ); document.write( "60 = 60 \n" ); document.write( "Answers check \n" ); document.write( "The number is 60 + 75 = 135\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |