document.write( "Question 882913: Jane needs 3 hours to clean the Smith house. Her younger sister, Alice, can clean the house in 5 hours. How long would the sisters, working together, need to clean the house? \n" ); document.write( "
Algebra.Com's Answer #533169 by Leaf W.(135)\"\" \"About 
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Hi!
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\n" ); document.write( "If Jane can clean the house in 3 hours, she is able to clean 1/3 of the house in an hour. Likewise, if Alice cleans the house in 5 hours, she can clean 1/5 of the house in an hour. Let us call the number of hours they need to clean the house (working together) x. Then, \"%281%2F3%29x\" is the fraction of the house Jane can clean in that amount of time, and \"%281%2F5%29x\" is the fraction of the house Alice can clean in that amount of time.
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\n" ); document.write( "Thus, you can create the equation \"%281%2F5%29x+%2B+%281%2F3%29x+=+1\", since you want the amount of the house Jane cleans plus the amount of the house Alice cleans to equal one (indicating one complete house). Now simply solve for x to find the amount of hours this will take:
\n" ); document.write( "\"x%2F5+%2B+x%2F3+=+1\"
\n" ); document.write( "Multiply by the least common denominator, 15: \"3x+%2B+5x+=+15\"
\n" ); document.write( "Add together like terms: \"8x+=+15\"
\n" ); document.write( "Divide both sides by 8: \"x+=+15%2F8\"
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\n" ); document.write( "Thus, the sisters need 15/8 hours to clean the house.
\n" ); document.write( "I hope this helps! =)
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