document.write( "Question 882692: How does the volume of a cone change when the radius is quadrupled and the height is reduced to 1/5 of its original size?\r
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Algebra.Com's Answer #533024 by KMST(5328)\"\" \"About 
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The volume, \"V\" , of a cone with radius \"r\" and height \"h\" is calculated as
\n" ); document.write( "\"V=%281%2F3%29%28pi%2Ar%5E2%29%2Ah\"
\n" ); document.write( "In that expression, \"pi%2Ar%5E2\" is the area of the base of the cone.
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\n" ); document.write( "If the radius is quadrupled, the new radius would be \"4r\" .
\n" ); document.write( "Then, the area of the base would be \"pi%2A%284r%5E2%29=pi%2A4%5E2%2Ar%5E3=pi%2A16%2Ar%5E2=16%2A%28pi%2Ar%5E2%29\" , and that would be \"16\" times more area for the base.
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\n" ); document.write( "If the height is reduced to \"1%2F5\" of the original height, the new height would be \"%281%2F5%29%2Ah\" .
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\n" ); document.write( "If the radius is quadrupled, and the height is reduced to \"1%2F5\" of the original height, the new cone volume will be
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\n" ); document.write( "That is \"16%2F5\" of the original cone's volume.
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