document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882674>Question 882674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular cutting board has an area of 112 square inches. Its perimeter is 44 inches. What are the dimensions of the cutting board? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #533017 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=533017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we are given two equations in two unknowns<BR>\n" );
document.write( "l * w = 112<BR>\n" );
document.write( "2l +2w = 44<BR>\n" );
document.write( "we can reduce the second equation by dividing both sides of = by 2<BR>\n" );
document.write( "l +w = 22<BR>\n" );
document.write( "then l = 22-w<BR>\n" );
document.write( "substitute for l in first equation<BR>\n" );
document.write( "(22-w) * w = 112<BR>\n" );
document.write( "22w -w^2 = 112<BR>\n" );
document.write( "w^2 -22w +112 = 0<BR>\n" );
document.write( "factor equation<BR>\n" );
document.write( "(w-8)*(w-14) = 112<BR>\n" );
document.write( "w = 8 or 14<BR>\n" );
document.write( "we have two solutions<BR>\n" );
document.write( "if w=8 inches, then l=14 inches<BR>\n" );
document.write( "if w=14 inches, then l=8 inches<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );