document.write( "Question 882676: If 5^(2x+1) ÷25= 125 find x
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Algebra.Com's Answer #532987 by josgarithmetic(39620)\"\" \"About 
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5^(2x+1) ÷25= 125
\n" ); document.write( "This is \"5%5E%282x%2B1%29%2F25=125\"
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\n" ); document.write( "\n" ); document.write( "\"5%5E%28%282x%2B1%29-2%29=5%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E%282x-1%29=5%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "Each member of the equation is the same base raised to what must be the same exponent. \"2x-1=3\". Go from there.
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