document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882514>Question 882514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FInd the exact value of tan(A-B) if cos(A)=3/5 where 0< or equal to A <or equal to pie/2 and sin(B)=(-5/13) where pie< or equal to B < or equal to 3pie/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532981 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FInd the exact value of tan(A-B) if cos(A)=3/5 where 0< or equal to A <or equal to pie/2 and sin(B)=(-5/13) where pie< or equal to B < or equal to 3pie/2<BR>\n" );
document.write( "***<BR>\n" );
document.write( "cos A=3/5 (working with a (3-4-5) reference right triangle in quadrant I)<BR>\n" );
document.write( "sinA=4/5<BR>\n" );
document.write( "..<BR>\n" );
document.write( "sinB=-5/13 (working with a (5-12-13) reference right triangle in quadrant III)<BR>\n" );
document.write( "cosB=-12/13<BR>\n" );
document.write( "..<BR>\n" );
document.write( "(sin(A-B)=sinAcosB-cosAsinB=4/5*(-12/13)-3/5*(-5/13)=-48/65+15/65=-33/65<BR>\n" );
document.write( "cos(A-B)=cosAcosB+sinAsinB=3/5*(-12/13)+4/5*(-5/13)=-36/65-20/65=56/65<BR>\n" );
document.write( "tan(A+B)=sin(A+B)/cos(A+B)=-33/56 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );