document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882557>Question 882557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can bike 4 miles in the same amount of time as it takes my friend to run 3 miles. If I can cycle 2 miles per hour faster than my friend, how fast can I cycle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532929 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532929\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I can bike 4 miles in the same amount of time as it takes my friend to run 3 miles. If I can cycle 2 miles per hour faster than my friend, how fast can I cycle?<BR>\n" );
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document.write( "let x=speed of runner<BR>\n" );
document.write( "x+2=speed of cyclist<BR>\n" );
document.write( "travel time=distance/speed (equal for both runner and cyclist)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "4/(x+2)=3/x<BR>\n" );
document.write( "4x=3x+6<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "x+2=8<BR>\n" );
document.write( "speed of cyclist=8 mph </SPAN>\n" );
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