document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=882386>Question 882386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of present age of two brothers 36 years. After four years their age will be 5:6. The age of the older brother ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #532813 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=532813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of present age of two brothers 36 years. After four years their age will be 5:6. The age of the older brother ?<BR>\n" );
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document.write( "let x=present age of younger brother<BR>\n" );
document.write( "36-x=present age of older brother<BR>\n" );
document.write( "After 4 yrs:<BR>\n" );
document.write( "x+4=age of younger brother<BR>\n" );
document.write( "36-x+4=40-x=age of older brother<BR>\n" );
document.write( "age of younger brother/age of older brother=5/6<BR>\n" );
document.write( "(x+4)/(40-x)=5/6<BR>\n" );
document.write( "6x+24=200-5x<BR>\n" );
document.write( "11x=176<BR>\n" );
document.write( "x=16<BR>\n" );
document.write( "36-16=20<BR>\n" );
document.write( "present age of older brother=20 </SPAN>\n" );
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