document.write( "Question 882376: flying with the wind a jet can travel 2800 miles in 4 hours flying against the wind the same distance take 6 hours find the rate of the yet and the wind \n" ); document.write( "

Algebra.Com's Answer #532800 by mananth(16946) $\"\"$ $\"About$

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Jet speed =x mph
\n" ); document.write( "wind speed =y mph
\n" ); document.write( "against wind 6 hours
\n" ); document.write( "with wind 4 hours
\n" ); document.write( "
\n" ); document.write( "Distance against 2800 miles distance with 2800 miles
\n" ); document.write( "t=d/r against wind -
\n" ); document.write( "2800.00 / ( x - y )= 6.00
\n" ); document.write( "6.00 ( x - y ) = 4.00
\n" ); document.write( "6.00 x - 6.00 y = 2800.00 ....................1
\n" ); document.write( "
\n" ); document.write( "2800.00 / ( x + y )= 4.00
\n" ); document.write( "4.00 ( x + y ) = 2800.00
\n" ); document.write( "4.00 x + 4.00 y = 2800.00 ...............2
\n" ); document.write( "Multiply (1) by 4.00
\n" ); document.write( "Multiply (2) by 6.00
\n" ); document.write( "we get
\n" ); document.write( "24.00 x + -24.00 y = 11200.00
\n" ); document.write( "24.00 x + 24.00 y = 16800.00
\n" ); document.write( "48.00 x = 28000.00
\n" ); document.write( "/ 48.00
\n" ); document.write( "x = 583.33 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "6.00 x -6.00 y = 2800.00
\n" ); document.write( "3500.00 -6.00 -3500.00 = 2800.00
\n" ); document.write( "-6.00 y = 2800.00
\n" ); document.write( "-6.00 y = -700.00 mph
\n" ); document.write( " y = 116.67
\n" ); document.write( "Jet speed 583.33 mph
\n" ); document.write( "wind speed 116.67 mph
\n" ); document.write( " \n" ); document.write( "

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