Algebra.Com's Answer #532725 by pj66(7)  You can put this solution on YOUR website! Let the no. be x. \n" );
document.write( "=> 2*x^2=11*x+21 \n" );
document.write( "since, twice the square of a no. is more than eleven times the number by 21. \n" );
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document.write( " | Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=289 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 7, -1.5.\n" );
document.write( "Here's your graph: \n" );
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