document.write( "Question 882141: Please help me to solve this problem. Given that (x + y)*2=63 and xy=65, find the value of x*2 + y*2 - 1. Thank you...
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Algebra.Com's Answer #532723 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Question almost looks like a rectangle problem.\r
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\n" ); document.write( "\n" ); document.write( "You want x and y solutions.\r
\n" ); document.write( "\n" ); document.write( "\"2x%2B2y=63\"
\n" ); document.write( "\"y=%2863-2x%29%2F2\"
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\n" ); document.write( "Substitute.
\n" ); document.write( "\"x%2863-2x%29%2F2=65\"
\n" ); document.write( "\"x%2863-2x%29=130\"
\n" ); document.write( "\"-2x%5E2%2B63x-130=0\"
\n" ); document.write( "\"2x%5E2-63x%2B130=0\"
\n" ); document.write( "D=(63)^2-4*2*130=3969-1040=2929=101*29
\n" ); document.write( "\"highlight%28x=%2863%2B-+sqrt%282929%29%29%2F%282%2A2%29%29\"
\n" ); document.write( "The results for x will be positive either way, so you might expect y to be the other value; the PLUS form is one dimension and the MINUS form is the other dimension. \r
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\n" ); document.write( "\n" ); document.write( "You can finish from that.
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