document.write( "Question 882170: Farhan's brother is three times as old as him. in 12 years' time, the sum of their ages will be equal to 10 times farhan's present ages. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #532720 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Farhan's brother is three times as old as him. in 12 years' time, the sum of their ages will be equal to 10 times farhan's present ages. find their present ages. \n" ); document.write( "*** \n" ); document.write( "let x=Farhan's present age \n" ); document.write( "3x=His brother's present age \n" ); document.write( ".. \n" ); document.write( "12 yrs from present: \n" ); document.write( "x+12=Farhan's age \n" ); document.write( "3x+12=Brother's age \n" ); document.write( "x+12+3x+12=10x \n" ); document.write( "4x+24=10x \n" ); document.write( "6x=24 \n" ); document.write( "x=4 \n" ); document.write( "3x=12 \n" ); document.write( "Farhan's present age=4 \n" ); document.write( "Brother's present age=12 \n" ); document.write( " |