document.write( "Question 882113: Suppose the half-life of a certain radioactive isotope is 11 minutes. If 21 per cent of the initial quantity is remaining, how many minutes old is the isotope?\r
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\n" ); document.write( "\n" ); document.write( "Answer: t = ?\r
\n" ); document.write( "\n" ); document.write( "Thanks so much!
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Algebra.Com's Answer #532707 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"A=Ie%5E%28-kt%29\" Exponential Decay Equation.
\n" ); document.write( "A = final amount
\n" ); document.write( "I = initial amount
\n" ); document.write( "t time in minutes
\n" ); document.write( "k = constant for the specific decaying material\r
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\n" ); document.write( "\n" ); document.write( "You know these values:
\n" ); document.write( "A=21
\n" ); document.write( "I=100
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\n" ); document.write( "The 11 minutes half life information allows you to find k.\r
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\n" ); document.write( "\n" ); document.write( "USE HALF LIFE TO FIND k.
\n" ); document.write( "\"ln%28A%29=ln%28I%29%2B%28-kt%29ln%28e%29\"
\n" ); document.write( "\"ln%28A%29-ln%28I%29=-kt%2A1\"
\n" ); document.write( "\"kt=ln%28I%29-ln%28A%29\"------you will use this again later.
\n" ); document.write( "\"k=%28ln%28I%29-ln%28A%29%29%2Ft\"
\n" ); document.write( "\"highlight_green%28k=%281%2Ft%29ln%28I%2FA%29%29\"---as a formula.
\n" ); document.write( "The half-life data meant I=1, A=1/2, t=11.
\n" ); document.write( "\"k=%281%2F11%29ln%281%2F%281%2F2%29%29=%281%2F11%29ln%282%29\"
\n" ); document.write( "\"k=0.06301\"
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\n" ); document.write( "Decay Equation Model, \"highlight_green%28A=Ie%5E%28-0.06301t%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "USE DECAY EQUATION TO ANSWER t.
\n" ); document.write( "Start from \"kt=ln%28I%29-ln%28A%29\";
\n" ); document.write( "\"highlight%28t=%281%2Fk%29ln%28I%2FA%29%29\";
\n" ); document.write( "Substitute the known values for k, I, and A; and compute t.
\n" ); document.write( "A=21, I=100, k=0.06301.
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